# How do you factor a perfect square trinomial X ²-6X +9?

As you noted ${x}^{2} - 6 x + 9$ is a perfect square,
namely ${\left(x - 3\right)}^{2}$
$\left(x - 3\right) \times \left(x - 3\right)$ are the factors of ${x}^{2} - 6 x + 9$