How do you factor and solve #-1x^2 -2x+35=0#?

1 Answer
May 26, 2016

Answer:

#x=5# or #x=-7#

Explanation:

To solve #-1x^2-2x+35=0#, we should first factorize the polynomial #-1x^2-2x+35#

To factorize a quadratic polynomial of type #ax^2+bx+c#,

one needs to split middle term #b# in two parts whose product is #ac#. As in #-1x^2-2x+35#, the product is #-35#, middle term #-2# can be split in #-7# and #5#.

Hence, #-1x^2-2x+35=0# can be written as

#-1x^2-7x+5x+35=0#

or #-x(x+7)+5(x+7)=0#

or #(-x+5)(x+7)=0#

i.e. #-x+5=0# or #x+7=0#

i.e. #x=5# or #x=-7#