Question

How do you factor and find the zeroes of the polynomial `y=-2x^4+10x^3-12x^2`?

Answer 1

Zeroes at `x= 3, x= 2 and x= 0`.

Explanation:

Factor out an `-2x^2`:

`y = -2x^2(x^2 - 5x + 6)`

`y = -2x^2(x - 3)(x - 2)`

Set to `0` and solve for `x`:

`0 = -2x^2(x - 3)(x- 2)`

`x = 0, 3 and 2`

This has zeroes at `x = 3, x = 2 and x = 0`.

Hopefully this helps!