How do you factor $ax – bx – 4a + 4b$ ?

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Answer 1 · 2018-03-11T12:12:27

$(x-4)(a-b)$

$ax-bx-4a+4b$

$=> x(a-b)-4(a-b)$

$=> (x-4)(a-b)$

Answer 2 · 2018-03-11T12:18:45

$(a-b)(x-4)$

$ax-bx-4a+4b$

Regroup the terms

$ax-4a+4b-bx$
$(ax-4a)+(4b-bx)$
$(ax-4a)-(bx-4b)$

Factorise $a$ and $b$ ,

$a(x-4)-b(x-4)$

Factorise $(x-4)$ ,

$(a-b)(x-4)$

There you have it!

How do you factor ax – bx – 4a + 4bax – bx – 4a + 4b?