How do you factor #(b+2)^2 - (b-2)^2#?

1 Answer
Dec 17, 2015

Answer:

Apply the difference of squares formula and simplify to find

#(b+2)^2 - (b-2)^2 = 8b#

Explanation:

The difference of squares formula states that
#a^2 - b^2 = (a+b)(a-b)#

In this case, we just happen to have binomials as #a# and #b#. However, the formula still applies.

#(b+2)^2 - (b-2)^2 = ((b+2)+(b-2))((b+2)-(b-2))#

#= (2b)(4)#

#= 8b#