# How do you factor #c^3 - 2c^2 - 8c#?

##### 2 Answers

The factorization of

#### Explanation:

To factor

begin by factoring out the variable

Next, factor the tri-nomial

by finding the factor of 8 that will subtract to get 2.

1 and 8 2 and 4

Since the second sign of the tri-nomial is subtraction the factors must have different signs.

Now factor the tri-nomial into two binomials.

Now complete the factors.

Here is a video on factoring.

#### Explanation:

Your starting expression looks like this

#c^3 - 2c^2 - 8c#

Notice that you can use *common factor* for all three terms. This will get you

#c * (c^2 - 2c - 8)#

Now focus on the paranthesis. Notice that you can rewrite that expression as

#c^2 - 2c - 8 = c^2 +2c - 4c - 8#

#=c * (c+2) * (-4) * (c + 2)#

#= (c + 2) * (c - 4)#

The expression can thus be factored as

#c^3 - 2c^2 - 8c = color(green)(c * (c+2) * (c-4))#