How do you factor completely #10m^2-21m-10#?
Ans: y = (5m - 2)(2m + 5)
I use the new AC Method to factor trinomials (Socratic Search)
(-2, 50)(-4, 25). This sum is 21 = -b. The opposite sum (b) gives p' = 4 and q' = -25.
Back to original trinomial,