How do you factor completely $10r^3s^2 + 25r^2s^2 – 15r^2s^3$ ?

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Answer 1 · 2017-05-15T06:11:37

$10r^3s^2+25r^2s^2-15r^2s^3 = 5r^2s^2(2r+5-3s)$

Given:

$10r^3s^2+25r^2s^2-15r^2s^3$

Note that all of the terms are divisible by $5$ , $r^2$ and $s^2$ , so by $5r^2s^2$ .

So we can separate that out as a factor:

$10r^3s^2+25r^2s^2-15r^2s^3 = 5r^2s^2(2r+5-3s)$

The remaining factor is already linear, so will not factor any further.

How do you factor completely 10r^3s^2 + 25r^2s^2 – 15r^2s^310r^3s^2 + 25r^2s^2 – 15r^2s^3?