How do you factor completely $121x^2 – 16$ ?

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Answer 1 · 2017-02-26T21:05:09

See complete solution explanation below:

This problem is in form:

$(a + b)(a - b) = a^2 - b^2$

Where $a^2 = 121x^2$ and $b^2 = 16$

Therefore:

$121x^2 - 16 = (11x + 4)(11x - 4)$

How do you factor completely 121x^2 – 16121x^2 – 16?