Question

How do you factor completely `121x^2 – 16`?

Answer 1

See complete solution explanation below:

Explanation:

This problem is in form:

`(a + b)(a - b) = a^2 - b^2`

Where `a^2 = 121x^2` and `b^2 = 16`

Therefore:

`121x^2 - 16 = (11x + 4)(11x - 4)`