# How do you factor completely #12y^2+9y+8y+6#?

##### 1 Answer

Nov 19, 2015

Factor by grouping to find:

#12y^2+9y+8y+6 = (3y+2)(4y+3)#

#### Explanation:

#12y^2+9y+8y+6#

#=(12y^2+9y)+(8y+6)#

#=3y(4y+3)+2(4y+3)#

#= (3y+2)(4y+3)#

Note that the hard work / fun has already been done for you in the split

If you are given something like