# How do you factor completely 14x^2 + 37x + 5?

Apr 13, 2018

The factors are (2x+5) and (7x+1).

#### Explanation:

By using the mid-term split method,

$14 {x}^{2} + 37 x + 5$

=$14 {x}^{2} + 2 x + 35 x + 5$

=$2 x \left(7 x + 1\right) + 5 \left(7 x = 1\right)$

= $\left(2 x + 5\right) \left(7 x + 1\right)$