How do you factor completely $14xy – 7x – 6y + 3$ ?

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Answer 1 · 2015-12-31T08:09:08

$=color(blue)((7x-3) (2y-1)$

$14xy-7x-6y+3$

We can factor this expression by making groups of two terms:
$color(blue)((14xy-7x)) + color(green)((-6y+3)$

$7x$ is common to both the terms in the first group, and $-3$ is common to both the terms in the second group:

$=7x(2y-1) -3 (2y-1)$

$(2y-1)$ is common to both the terms now
$=color(blue)((7x-3) (2y-1)$

How do you factor completely 14xy – 7x – 6y + 3 14xy – 7x – 6y + 3?