How do you factor completely 16x^2-81?

1 Answer
smendyka
Jan 13, 2017

See full factoring process below:

Explanation:

Because there is no x term and the constant term is a negative we know the sum of the factored x terms is 0. And, because both the x^2 coefficient and the constant are squares this expression can be factored as:

(ax + b)(ax - b) or

(4x + 9)(4x - 9)

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