# How do you factor completely 16x^3-10x^2-8x?

Sep 23, 2017

$2 x \left(8 {x}^{2} - 5 x - 4\right)$

#### Explanation:

Since this expression has no constant, you can factor out $2 x$:

$16 {x}^{3} - 10 {x}^{2} - 8 x$

$= 2 x \left(8 {x}^{2} - 5 x - 4\right)$

And in this case, you can't factor the quadratic any further, so the cubic expression is as factored as possible.