How do you factor completely $16x^3-10x^2-8x$ ?

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Answer 1 · 2017-09-23T03:30:40

$2x(8x^2-5x-4)$

Since this expression has no constant, you can factor out $2x$ :

$16x^3 -10x^2 -8x$

$=2x(8x^2-5x-4)$

And in this case, you can't factor the quadratic any further, so the cubic expression is as factored as possible.

How do you factor completely 16x^3-10x^2-8x16x^3-10x^2-8x?