How do you factor completely $18 a^{2} b e^{2} - 48 a b c^{3}$ $18a^2be^2-48abc^3$ ?

Question

1487 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-15T04:54:02

$\Rightarrow 6 a b (3 a e^{2} - 8 c^{3})$ $color(crimson)(=> 6 ab(3ae^2 - 8 c^3)$

$18 a \land 2 b e^{2} - 48 a b c^{3}$ $18a^^2be^2 - 48abc^3$

$\Rightarrow 6 \cdot 3 \cdot a \cdot a \cdot b \cdot e^{2} - 6 \cdot 8 \cdot a 8 b \cdot c^{3}$ $=> 6 * 3 * a * a * b * e^2 - 6 * 8 * a 8 b * c^3$

$\Rightarrow 6 a b (3 a e^{2} - 8 c^{3}), Taking common terms out$ $color(crimson)(=> 6 ab(3ae^2 - 8 c^3), " Taking common terms out"$

How do you factor completely 18a^2be^2-48abc^318a2be2−48abc318a^2be^2-48abc^3?