How do you factor completely #20x^2 + 22xy + 6y^2#?
Ans: 2(2x + y)(5x + 3y)
I use the new AC Method to factor trinimilas (Socratic Search)
p' and q' have same sign. Factor pairs of (30y^2) --> (5y, 6y). This sum is 11y = b. Then p' = 5y and q' = 6y.