# How do you factor completely 20y^6+ 12y^4?

$4 {y}^{4} \left(5 {y}^{2} + 3\right)$

#### Explanation:

Within the statement:

$20 {y}^{6} + 12 {y}^{4}$

What is common in both terms? I'm going to rewrite the terms to help see it:

$\left(2 \times 2 \times 5 \times {y}^{4} \times {y}^{2}\right) + \left(2 \times 2 \times 3 \times {y}^{4}\right)$

What's common is ${y}^{4}$ and $2 \times 2 = 4$. Let's factor those out:

$4 {y}^{4} \left(5 {y}^{2} + 3\right)$