How do you factor completely $20y^6+ 12y^4$ ?

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Answer 1 · 2016-12-23T02:30:00

$4y^4(5y^2+3)$

Within the statement:

$20y^6+12y^4$

What is common in both terms? I'm going to rewrite the terms to help see it:

$(2xx2xx5xxy^4xxy^2)+(2xx2xx3xxy^4)$

What's common is $y^4$ and $2xx2=4$ . Let's factor those out:

$4y^4(5y^2+3)$

How do you factor completely 20y^6+ 12y^420y^6+ 12y^4?