Question

How do you factor completely `22y^4-33y^3+11y^2`?

Answer 1

It is

#22y^4-33y^3+11y^2=22y^4-22y^3-11y^3+11y^2= 22y^3(y-1)-11y^2(y-1)=(22y^3-11y^2)*(y-1)= 11y^2(2y-1)*(y-1)#