How do you factor completely #27+8t^3#? Algebra Polynomials and Factoring Factoring Completely 1 Answer EZ as pi Sep 16, 2016 #27 + 8t^3 = (3+2t)(9-6t+4t^2)# Explanation: #27, 8 and t^3# are all cubes. Once you recognise that fact, you can factorise this expression by the general rule for "Sum of cubes". #x^3 +y^3 = (x+y)(x^2-xy+y^2)# #27 + 8t^3 = (3+2t)(9-6t+4t^2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1244 views around the world You can reuse this answer Creative Commons License