How do you factor completely 2a2−4a−2?
1 Answer
Oct 28, 2016
Explanation:
The difference of squares identity can be written:
A2−B2=(A−B)(A+B)
Use this with
2a2−4a−2=2(a2−2a−2)
2a2−4a−2=2(a2−2a+1−3)
2a2−4a−2=2((a−1)2−(√3)2)
2a2−4a−2=2((a−1)−√3)((a−1)+√3)
2a2−4a−2=2(a−1−√3)(a−1+√3)