How do you factor completely #2ax^2 - 24ax + 72a#?

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Answer 1 · 2018-04-19T07:42:10

#2a(x-6)^2#

#"take out a "color(blue)"common factor "2a#

#=2a(x^2-12x+36)#

#"the factors of + 36 which sum to - 12 are - 6 and - 6"#

#=2a(x-6)(x-6)=2a(x-6)^2#

Answer 2 · 2018-04-19T07:43:00

See below

#2ax^2-24ax-72a=2a(x^2-12x+36)=2a(x-6)^2# because

#(a-b)^2=a^2-2ab+b^2# for #a=x# and #b=6#