How do you factor completely #2ax^2 - 24ax + 72a#?

2 Answers
Apr 19, 2018

Answer:

#2a(x-6)^2#

Explanation:

#"take out a "color(blue)"common factor "2a#

#=2a(x^2-12x+36)#

#"the factors of + 36 which sum to - 12 are - 6 and - 6"#

#=2a(x-6)(x-6)=2a(x-6)^2#

Apr 19, 2018

Answer:

See below

Explanation:

#2ax^2-24ax-72a=2a(x^2-12x+36)=2a(x-6)^2# because

#(a-b)^2=a^2-2ab+b^2# for #a=x# and #b=6#