# How do you factor completely: 2cb + 7cx + 2b + 7x?

I found: $\left(2 b + 7 x\right) \left(c + 1\right)$
Try collecting $c$ between the first and second term:
$c \left(2 b + 7 x\right) + \left(2 b + 7 x\right) =$
$= \left(2 b + 7 x\right) \left(c + 1\right)$