# How do you factor completely 2x^2-18?

Jul 6, 2016

$2 \left(x + 3\right) \left(x - 3\right)$

#### Explanation:

To factor $2 {x}^{2} - 18$

Begin by factoring out the 2 from each term

$2 \left({x}^{2} - 9\right)$

Now we recognize that ${x}^{2} - 9$ is the difference of two squares
$x \cdot x$ and $3 \cdot 3$

This factors to

$2 \left(x + 3\right) \left(x - 3\right)$