# How do you factor completely 2x^2+50y^2-20xy?

Aug 28, 2016

$2 {x}^{2} + 50 {y}^{2} - 20 x y = 2 {\left(x - 5 y\right)}^{2}$

#### Explanation:

Separate out the common scalar factor $2$, rearrange into stanard order and notice a perfect square trinomial...

$2 {x}^{2} + 50 {y}^{2} - 20 x y$

$= 2 \left({x}^{2} - 10 x y + 25 {y}^{2}\right)$

$= 2 \left({x}^{2} - 2 \left(x\right) \left(5 y\right) + {\left(5 y\right)}^{2}\right)$

$= 2 {\left(x - 5 y\right)}^{2}$