How do you factor completely #2x^2+50y^2-20xy#?
1 Answer
Aug 28, 2016
Explanation:
Separate out the common scalar factor
#2x^2+50y^2-20xy#
#= 2(x^2-10xy+25y^2)#
#= 2(x^2-2(x)(5y)+(5y)^2)#
#= 2(x-5y)^2#