How do you factor completely #2x^2+6x-80#?
y = 2(x - 5)( x + 8)
Factor the trinomial in parentheses.
Find 2 numbers knowing sum (b = 3) and product (c = -40).
They are (-5, 8).
y = 2(x - 5)(x + 8)
First observe that all the terms have a constant factor of
so we can write:
Next lets think about factors of
and the middle term
Therefore our complete factors are: