How do you factor completely: #-2x^3 + 6x^2#?

1 Answer
Apr 3, 2018

Answer:

#-2x^2(x-3)#

Explanation:

#-2x^3+6x^2#

To factor this, we have to see what is in common.

If you divide them both by #-2#, you will get #x^3 - 3x^2#. So now it becomes #-2(x^3-3x^2)#.

As you can see, we can still take out a #x^2#. So now the factored form is this:
#-2x^2(x-3)#

Hope this helps!