How do you factor completely: $-2x^3 + 6x^2$ ?

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Answer 1 · 2018-04-03T22:20:27

$-2x^2(x-3)$

$-2x^3+6x^2$

To factor this, we have to see what is in common.

If you divide them both by $-2$ , you will get $x^3 - 3x^2$ . So now it becomes $-2(x^3-3x^2)$ .

As you can see, we can still take out a $x^2$ . So now the factored form is this:
$-2x^2(x-3)$

Hope this helps!

How do you factor completely: -2x^3 + 6x^2-2x^3 + 6x^2?