# How do you factor completely: -2x^3 + 6x^2?

Apr 3, 2018

$- 2 {x}^{2} \left(x - 3\right)$

#### Explanation:

$- 2 {x}^{3} + 6 {x}^{2}$

To factor this, we have to see what is in common.

If you divide them both by $- 2$, you will get ${x}^{3} - 3 {x}^{2}$. So now it becomes $- 2 \left({x}^{3} - 3 {x}^{2}\right)$.

As you can see, we can still take out a ${x}^{2}$. So now the factored form is this:
$- 2 {x}^{2} \left(x - 3\right)$

Hope this helps!