# How do you factor completely #2x^3y^4 − 8x^2y^3 + 6xy^2#?

##### 1 Answer

Aug 18, 2016

#### Explanation:

Separate out the common factor

#2x^3y^4-8x^2y^3+6xy^2#

#=2xy^2(x^2y^2-4xy+3)#

#=2xy^2((xy)^2-4(xy)+3)#

#=2xy^2(xy-3)(xy-1)#