Question

How do you factor completely `2y^3+8y^2-64y`?

Answer 1

Factors are 2, y, y+8, y-4

Explanation:

Please, have a look how the given figure can be broken down:
`2y^3+8y^2−64y = 2y(y^2+4y-32) = 2y(y^2+8y-4y-32) = 2y{y(y+8)-4(y+8) = 2y(y+8)(y-4)`