How do you factor completely $36+3x-3x^2$ ?

Question

1351 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-30T04:13:10

Factor $y = -3x^2 + 3x + 36 = -3(x^2 - x - 12)$

Factor $f(x) = x^2 - x - 12.$
Compose factor pairs of (-12) --> (-2, 6)(-3, 4). This sum is 1 = -b. Then the factor are (x + 3) and (x - 4)

y = -3(x + 3)(x - 4)

How do you factor completely 36+3x-3x^236+3x-3x^2?