# How do you factor completely 3x^2 + 4x -15?

$\textcolor{w h i t e}{\times} 3 {x}^{2} + 4 x - 15 = 3 \left(x - \frac{5}{3}\right) \left(x + 3\right)$
$\textcolor{w h i t e}{\times} 3 \left(x - \frac{5}{3}\right) \left(x + 3\right) = 3 \left({x}^{2} + 3 x - \frac{5 x}{3} - 5\right)$
$\textcolor{w h i t e}{\times \times \times \times \times \times \times} = 3 \left({x}^{2} + \frac{9 x - 5 x}{3} - 5\right)$
$\textcolor{w h i t e}{\times \times \times \times \times \times \times} = 3 {x}^{2} + 4 x - 15$