How do you factor completely $3x^2+4x-4+=0$ ?

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Answer 1 · 2018-06-30T22:38:47

$x=-2$ and $x=2/3$

We can use factoring by grouping. Here I will rewrite the $b$ term as the sum of two terms so we can factor.

Our quadratic can be alternatively written as

$color(turquoise)(3x^2-2x)+color(orange)(6x-4)=0$

We can factor an $x$ out of the light blue term, and a $2$ out of the orange term. This gives us

$color(turquoise)(x(3x-2))+color(orange)(2(3x-2))=0$

We can factor out a $3x-2$ to get

$(3x-2)(x+2)=0$

Setting both factors equal to zero, we get

$x=-2$ and $x=2/3$

Hope this helps!

How do you factor completely 3x^2+4x-4+=03x^2+4x-4+=0?