How do you factor completely $3x^2 + 5x + 1$ ?

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Answer 1 · 2016-04-07T12:53:29

Not factorable

$D = b^2 - 4ac = 25 - 12 = 13$
Since D is not a perfect square, this trinomial can't be factored.

How do you factor completely 3x^2 + 5x + 13x^2 + 5x + 1?