# How do you factor completely 3x^2+6x-24?

$3 {x}^{2} + 6 x - 24 = 3 \left(x + 4\right) \left(x - 2\right)$
Note that all of the terms are divisible by $3$, so we can separate that out as a factor first, then note that $8$ is the product of $4$ and $2$, which differ by $2$, so we find:
$3 {x}^{2} + 6 x - 24 = 3 \left({x}^{2} + 2 x - 8\right) = 3 \left(x + 4\right) \left(x - 2\right)$