How do you factor completely: $3x^2 + y$ ?

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Answer 1 · 2015-07-22T20:51:10

$(sqrt(3)x-isqrt(y))(sqrt(3)x+isqrt(y))$

No natural factoring here. You could factor this as the difference of 2 squares:

$3x^2+y=(sqrt(3)x-isqrt(y))(sqrt(3)x+isqrt(y))$

How do you factor completely: 3x^2 + y3x^2 + y?