Question

How do you factor completely: `3x^2 + y`?

Answer 1

`(sqrt(3)x-isqrt(y))(sqrt(3)x+isqrt(y))`

Explanation:

No natural factoring here. You could factor this as the difference of 2 squares:

`3x^2+y=(sqrt(3)x-isqrt(y))(sqrt(3)x+isqrt(y))`