# How do you factor completely 3x^3-19x^2-14x?

$= x \left(x - 7\right) \left(3 x + 2\right)$
$3 {x}^{3} - 19 {x}^{2} - 14 x$
$= x \left(3 {x}^{2} - 19 x - 14\right)$
$= x \left(3 {x}^{2} - 21 x + 2 x - 14\right)$
$= x \left(3 x \left(x - 7\right) + 2 \left(x - 7\right)\right)$
$= x \left(x - 7\right) \left(3 x + 2\right)$