How do you factor completely $3x^3-19x^2-14x$ ?

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Answer 1 · 2016-05-07T17:22:30

$=x(x-7)(3x+2)$

$3x^3-19x^2-14x$
$=x(3x^2-19x-14)$
$=x(3x^2-21x+2x-14)$
$=x(3x(x-7)+2(x-7))$
$=x(x-7)(3x+2)$

How do you factor completely 3x^3-19x^2-14x3x^3-19x^2-14x?