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How do you factor completely $3x^3 + 24x^2 - 99x$ ?

1 Answer

Apr 28, 2017

$3x(x+11)(x-3)$

Explanation:

$3x^3+24x^2-99x$
$=3x(x^2+8x-33)$
$=3x(x+11)(x-3)$

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