How do you factor completely $3xy-4x+6y-8$ ?

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Answer 1 · 2018-06-13T15:15:35

$(x+2)(3y-4)$

$3xy-4x+6y-8$

rearrange:

$3xy+6y-4x-8$

factor by grouping:

$3y(x+2)-4(x+2)$

factor out $(x+2)$

$(x+2)(3y-4)$

How do you factor completely 3xy-4x+6y-83xy-4x+6y-8?