How do you factor completely $49x^2 - 25y^2$ ?

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Answer 1 · 2018-03-28T11:00:57

$(7x-5y)(7x+5y)$

Given: $49x^2-25y^2$

Apply the identity: $a^2-b^2=(a-b)(a+b)$

Here, $a^2=49x^2,b^2=25y^2$

$:.a=sqrt(49x^2)=7x,b=sqrt(25y^2)=5y$

And so,

$49x^2-25y^2=(7x-5y)(7x+5y)$

How do you factor completely 49x^2 - 25y^249x^2 - 25y^2?