How do you factor completely 4ax + 8ay + 3bx + 6by ?

Nov 19, 2015

Factor by grouping to find:

$4 a x + 8 a y + 3 b x + 6 b y = \left(4 a + 3 b\right) \left(x + 2 y\right)$

Explanation:

Notice that the first two terms are both divisible by $4 a$ and the last two terms are both divisible by $3 b$, so try factoring by grouping:

$4 a x + 8 a y + 3 b x + 6 b y$

$= \left(4 a x + 8 a y\right) + \left(3 b x + 6 b y\right)$

$= 4 a \left(x + 2 y\right) + 3 b \left(x + 2 y\right)$

$= \left(4 a + 3 b\right) \left(x + 2 y\right)$