How do you factor completely #4ax + 8ay + 3bx + 6by #?
1 Answer
Nov 19, 2015
Factor by grouping to find:
#4ax+8ay+3bx+6by=(4a+3b)(x+2y)#
Explanation:
Notice that the first two terms are both divisible by
#4ax+8ay+3bx+6by#
#=(4ax+8ay)+(3bx+6by)#
#=4a(x+2y)+3b(x+2y)#
#=(4a+3b)(x+2y)#