How do you factor completely 4b^4-1024?
1 Answer
Apr 18, 2016
Explanation:
The first step is to take out the common factor of 4.
rArr 4(b^4 - 256) now
(b^4 - 256)" is a difference of squares "
since
a difference of squares factors as follows
color(red)(|bar(ul(color(white)(a/a)color(black)( a^2 - b^2 = (a - b)(a + b))color(white)(a/a)|))) here a
= b^2" and b = 16
rArr b^4 - 256 = (b^2 - 16)(b^2 + 16) now
b^2 - 16" is also a difference of squares " and factors as
(b - 4)(b + 4) Putting this together gives
4b^4 - 1024 = 4(b^2 +16)(b - 4)(b + 4)