How do you factor completely #4b^4-1024#?
1 Answer
Apr 18, 2016
Explanation:
The first step is to take out the common factor of 4.
#rArr 4(b^4 - 256) # now
#(b^4 - 256)" is a difference of squares " #
since
a difference of squares factors as follows
#color(red)(|bar(ul(color(white)(a/a)color(black)( a^2 - b^2 = (a - b)(a + b))color(white)(a/a)|)))# here a
#= b^2" and b = 16 #
#rArr b^4 - 256 = (b^2 - 16)(b^2 + 16) # now
#b^2 - 16" is also a difference of squares " # and factors as
# (b - 4)(b + 4) # Putting this together gives
#4b^4 - 1024 = 4(b^2 +16)(b - 4)(b + 4) #