How do you factor completely 4b^4-1024?

1 Answer
Apr 18, 2016

4(b^2 + 16)(b - 4)(b + 4)

Explanation:

The first step is to take out the common factor of 4.

rArr 4(b^4 - 256)

now (b^4 - 256)" is a difference of squares "

since b^4 = b^2xxb^2" and " 256 = 16xx16

a difference of squares factors as follows

color(red)(|bar(ul(color(white)(a/a)color(black)( a^2 - b^2 = (a - b)(a + b))color(white)(a/a)|)))

here a = b^2" and b = 16

rArr b^4 - 256 = (b^2 - 16)(b^2 + 16)

now b^2 - 16" is also a difference of squares "

and factors as (b - 4)(b + 4)

Putting this together gives

4b^4 - 1024 = 4(b^2 +16)(b - 4)(b + 4)