How do you factor completely #4x^2- 13x + 10#?

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Answer 1 · 2015-11-20T09:56:55

#(x-2)(4x-5)#

#4x^2-13x+10#

Multiply co-efficent of #x^2# with the constant term #10#

It is #40#
The co-efficeint of #x=-13#

You have to find two numbers the product of those two numbers must be equal to #40# and the sum of the two numbers must be equal to #-13#

They are #-8, -5#

Now rewrite the expression as -

#4x^2 -5x-8x+10#

Factor it -

#x(4x-5)-2(4x-5)#

#(x-2)(4x-5)#