# How do you factor completely 4x^2- 13x + 10?

Nov 20, 2015

$\left(x - 2\right) \left(4 x - 5\right)$

#### Explanation:

$4 {x}^{2} - 13 x + 10$

Multiply co-efficent of ${x}^{2}$ with the constant term $10$

It is $40$
The co-efficeint of $x = - 13$

You have to find two numbers the product of those two numbers must be equal to $40$ and the sum of the two numbers must be equal to $- 13$

They are $- 8 , - 5$

Now rewrite the expression as -

$4 {x}^{2} - 5 x - 8 x + 10$

Factor it -

$x \left(4 x - 5\right) - 2 \left(4 x - 5\right)$

$\left(x - 2\right) \left(4 x - 5\right)$