How do you factor completely #4x^3y^2 + 12xy^2 + 20x^2y^3 #?

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Answer 1 · 2018-03-12T12:58:35

#4xy^2(x^2 + 3+ 5xy)#

#4x^3y^2 + 12xy^2 + 20x^2y^3#

Factorise #4#,

#4(x^3y^2 + 3xy^2 + 5x^2y^3)#

Factorise #x#,

#4x(x^2y^2 + 3y^2 + 5xy^3)#

Factorise #y^2#,

#4xy^2(x^2 + 3+ 5xy)#