How do you factor completely $4x^3y^2 + 12xy^2 + 20x^2y^3$ ?

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Answer 1 · 2018-03-12T12:58:35

$4xy^2(x^2 + 3+ 5xy)$

$4x^3y^2 + 12xy^2 + 20x^2y^3$

Factorise $4$ ,

$4(x^3y^2 + 3xy^2 + 5x^2y^3)$

Factorise $x$ ,

$4x(x^2y^2 + 3y^2 + 5xy^3)$

Factorise $y^2$ ,

$4xy^2(x^2 + 3+ 5xy)$

How do you factor completely 4x^3y^2 + 12xy^2 + 20x^2y^3 4x^3y^2 + 12xy^2 + 20x^2y^3 ?