How do you factor completely #5x^2 - 23 x + 12#?
1 Answer
Mar 17, 2016
Use an AC method and factor by grouping to find:
#5x^2-23x+12=(5x-3)(x-4)#
Explanation:
We can use an AC method.
Look for a pair of factors of
The pair
Use this pair to split the middle term and factor by grouping as follows:
#5x^2-23x+12#
#=5x^2-20x-3x+12#
#=(5x^2-20x)-(3x-12)#
#=5x(x-4)-3(x-4)#
#=(5x-3)(x-4)#
