How do you factor completely #5x^2-5x-100#?

Question

3627 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-18T12:14:45

#5(x-5)(x +4)#

#color(white)(xx)5x^2 - 5x - 100#

#= 5(x^2 - x - 20)# [First take the common part out]

#= 5{x^2 - (5 - 4)x - 20}# [We can write #1# as #(5 - 4)#]

#= 5{x^2 - 5x + 4x - 20}# [Multiply using Distributive Property]

#= 5{x(x - 5) + 4(x - 5)}# [Put the like terms in group]

#= 5(x - 5)(x + 4)# [Group #(x - 5)# terms]

And we got our answer. Hope this helps.