How do you factor completely # 6x^2 + 18xy + 12y^2#?

1 Answer
Jun 21, 2016

Answer:

#6(x + 2y)(x + y)#

Explanation:

Always look to see if there is a common factor first.
In this case you can divide out a factor of 6 from all the terms.

#6(x^2 + 3xy +2y^2)#

Now, the factors of 2 which add up to 3 are 2 and 1.
The signs are the same, they are both positive.
There will be an x and a y term in each bracket.

#6(x + 2y)(x + y)#