# How do you factor completely 6x^2+5x+1?

Apr 16, 2016

$6 {x}^{2} + 5 x + 1 = \left(2 x + 1\right) \left(3 x + 1\right)$
Note that $2 + 3 = 5$ and $2 \times 3 = 6$
$6 {x}^{2} + 5 x + 1 = \left(2 x + 1\right) \left(3 x + 1\right)$