# How do you factor completely #6x^3 - 10x^2 + 9x - 15#?

##### 1 Answer

Nov 19, 2015

#### Answer:

Factor by grouping to find:

#6x^3-10x^2+9x-15#

#=(2x^2+3)(3x-5)#

#=(sqrt(2)x-sqrt(3)i)(sqrt(2)x+sqrt(3)i)(3x-5)#

#### Explanation:

#6x^3-10x^2+9x-15#

#=(6x^3-10x^2)+(9x-15)#

#=(2x^2(3x-5)+3(3x-5)#

#=(2x^2+3)(3x-5)#

If we allow Complex coefficients then

#2x^2+3 = (sqrt(2)x-sqrt(3)i)(sqrt(2)x+sqrt(3)i)#