How do you factor completely #77x^2+102x+16#?

1 Answer
Jan 5, 2016

Answer:

#(11x + 2)(7x + 8)#

Explanation:

If the factored form of a quadratic is #y = (ax+b)(cx+d)#
the standard form is #acx^2 +(ad+bc)x +bd#
In this example therefore we need to find factors of #77 (ac)# and #16 (bd)# that add to give #102 (ad + bc)#
#77 = 7 * 11# and #16 = 8*2#
#11*8 +7*2 = 88 + 14 = 102#
The result is therefore #(11x + 2)(7x + 8)#