How do you factor completely #81x^2 – 100#?

1 Answer
Jun 10, 2016

Answer:

#(9x+10)(9x-10)#

Explanation:

To factor #81x^2-100# we must first recognize that this is the difference (subtraction) of two perfect squares.

#81x^2 = (9x)(9x)#
#100=(10)(10)#

When we factors the difference of two squares the binomials always have one #+# and one #-#.

#(9x+10)(9x-10)#