How do you factor completely #8w^3 - 4w^2 - 60w#?

1 Answer
Jul 31, 2016

Answer:

#4w(2w+5)(w-3)#

Explanation:

Always look for a common factor first. In this case it is #4w#

#8w^3 - 4w^2 - 60w = 4w(2w^2 -w -15)#

Now, find factors of 2 and 15 which subtract to give 1.
There must be more negatives.

find the cross products and subtract.
#" 2 5 "rArr 1xx5 = 5#
#" 1 3 "rArr2 xx3 = 6" 6-5 = 1"#

But we need #-1," 6 must be negative and 5 must be positive"#

=#4w(2w+5)(w-3)#